WebIn an A.P, if the pth term is 1/q and qth term is 1/p, prove that the sum of first pq terms is 1/2 (pq + 1), where p ≠ q.We have proven that the sum pq terms in the series are 1/2 (pq + 1). … WebMar 29, 2024 · Show that (q r) a+ (r p)b+ (p q) c = 0 Here we have small a in the equation, so we use capital A for first term We know that, An = A + (n 1) D where An is the nth term of A.P. n is the number of terms A is the first term, D is the common difference It is given that pth term of an AP is a i.e. Ap = a Putting n = p A + (p 1) D = a a = A + (p 1)D …

[Solved] The sum of (p + q)th and (p – q)th terms of an AP is e

WebResult. The results showed that HFD group had a higher body weight than LFD group after 8, 14, and 16 weeks of feeding. Furthermore, at the final observation, there were statistically significant differences between LFD group and HFD group in terms of total cholesterol (TC), triglycerides (TG), low-density lipoprotein (LDL), and high-density lipoprotein (HDL) levels. WebFeb 10, 2024 · In an A.P., if pth term is 1/q and qth term is 1/p, prove that the sum of first pq terms is ½ (pq +1), where p ≠ q. sequences and series class-11 1 Answer +1 vote answered Feb 10, 2024 by sameer (54.7k points) selected Feb 13, 2024 by sanjeev Best answer patricia compton canmore

If the pth term of an AP is q and the qth term is p, prove …

WebMar 30, 2024 · Transcript. Example 21 If pth, qth, rth and sth terms of an A.P. are in G.P, then show that (p – q), (q – r), (r – s) are also in G.P. We know that the nth term of AP is a + (n – 1)d i.e. an = a + (n – 1)d It is given that ap, aq, ar & as in GP i.e. their common ratio is same So,𝑎_𝑞/𝑎_𝑝 = (ar )/qq = 𝑎𝑠/𝑎𝑟 We need to show (p – q), (q – r), (r – s) are in ... WebOct 29, 2024 · pth term of an AP = q qth term = p Prove: nth term of A.P. is (p+q-n). Proof: We know that, nth term of an AP (an) = a + (n - 1)d Hence, a + (p - 1)d = q a + pd - d = q a = q - pd + d -- equation (1) Similarly, a + (q - 1)d = p Substitute the value of a from equation (1). q - pd + d + qd - d = p qd - pd = p - q - d(p - q) = p - q - d = 1 WebIf the pth, qth and rth terms of an A.P. be a, b and c respectively, then prove that a(q−r)+b(r−p)+c(p−q)=0. Medium Solution Verified by Toppr Let A be the first term and D the common difference of A.P. T p=a=A+(p−1)D=(A−D)+pD (1) T q=b=A+(q−1)D=(A−D)+qD ..(2) T r=c=A+(r−1)D=(A−D)+rD ..(3) patricia comercial